1) rational algebraic variety
有理代数簇
2) rational function over a variety
簇上有理函数
3) algebraic variety
代数簇
1.
As a consequence of the above result,we have that implicative semilattices form an algebraic variety.
作为一个推论给出:蕴涵半格构成一个代数簇。
4) algebraic varieties
代数簇
1.
,x n], P=Q the root ideal of Q and J the subset of ring assume Q∩J≠ , then the algebraic varieties of idea quotient V(Q∶J)= .
设Q是多项式环k[x1 ,x2 ,… ,xn]中的P 准素理想 ,P =Q是理想Q的根理想 ,J是k[x1 ,x2 ,… ,xn]的子集 ,若Q∩J≠ ,则Q对J的商理想Q∶J的代数簇V(Q∶J) = ;若Q∩J = ,则Q∶J的代数簇V(Q∶J) =V(Q∶J) ;若P∩J= ,则V(Q∶J) =V(Q) 。
5) quasi-algebraic variety
拟代数簇
1.
In this paper by applying some equivalent formulas in first-order logic,this problem is transformed into one which checks whether another quasi-algebraic variety is empty.
判定拟代数簇的包含关系问题不能由计算其相应的饱和理想来确定 。
6) variety of universal algebras
泛代数簇
补充资料：有理
1.有道理。
说明：补充资料仅用于学习参考，请勿用于其它任何用途。
参考词条