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1)  grid decking
梁格工桥面系
2)  steel I-Beam Bridge with timber floor
工字钢梁木面桥
3)  composite beam bridge deck system
组合梁桥面系
4)  skew grillage girder bridge
斜格梁桥
5)  bridge deck
桥梁断面
1.
Numerical simulations for aerodynamic derivatives and critical flutter velocity of bridge deck;
数值模拟桥梁断面气动导数和颤振临界风速
2.
An improved stochastic subspace identification method for flutter derivatives of bridge decks
桥梁断面气动导数识别的改进随机子空间法
3.
Nowadays, either wind tunnel tests or CFD (Computational Fluid Dynamics) simulations are time-consuming and inefficient to identify bridge deck flutter derivatives, since a large number of tests or simulations must be performed repeatedly at various reduced wind speeds.
由于需要在不同折算风速下重复进行大量试验或CFD(Computational Fluid Dynamics)模拟,现有风洞试验和CFD方法识别桥梁断面颤振导数耗时且效率低。
6)  bridge deck section
桥梁断面
1.
Numerical assessment of static wind loads on bridge deck section based on lattice Boltzmann method
桥梁断面静风荷载的格子Boltzmann方法数值计算
2.
This paper measures the drag, lift and moment of two kinds of typical bridge deck sections with different ratios of width to height (B/H) in TJ-2 wind tunnel.
在TJ- 2风洞中 ,测量了近 2个数量级的雷诺数范围内不同宽高比的 2类桥梁断面的三分力 ;研究了桥梁断面三分力系数雷诺数效应、宽高比对断面三分力系数雷诺数效应的影响 。
3.
Aerodynamically coupling flutter analysis and flutter mechanism for bridge deck sections;
通过对系统竖向和扭转耦合振动运动方程的解耦,将系统振动参数的频率和阻尼比隐式地表达成桥梁断面颤振导数的函数形式,导出了二自由度耦合颤振分析方法。
补充资料:ANSYS工字梁焊缝初应力例子

建立好模型
…..
/SOLU
!*
ANTYPE,0
/INPUT,'input','txt',
/INPUT,'output1','txt',
!*
ISFILE,READ,1,txt, ,0
SOLVE
=====================
!定义残余应力矩阵
I=1
fy=310e6
!定义单元中心坐标数组,初应力数组
*DIM,EleCenter,ARRAY,NumNode,3,1, , ,
*DIM,EleIS,ARRAY,NumNode,1,1, , ,
*DO,I, 1, NumNode,1
!得到单元中心坐标
*GET,EleCenter(I,1,1),ELEM,I,CENT,X
*GET,EleCenter(I,2,1),ELEM,I,CENT,Y
*GET,EleCenter(I,3,1),ELEM,I,CENT,Z
!焊缝位置在X=1.0 到1.05 之间
*IF,EleCenter(I,1,1),GT,1,THEN
*IF,EleCenter(I,1,1),LT,1.05,THEN
*IF,EleCenter(I,2,1),GT,0.5,THEN
!上翼缘初始应力
EleIS(I,1,1)=-20*fy*EleCenter(I,3,1)**2+0.3*fy
*endif
*IF,EleCenter(I,2,1),LT,0.0,THEN
!下翼缘初始应力
EleIS(I,1,1)=-20*fy*EleCenter(I,3,1)**2+0.3*fy
*endif
!腹板初始应力
*if,EleCenter(I,2,1),GE,0.0,THEN
*IF,ELECENTER(I,2,1),LE,0.5,THEN
EleIS(I,1,1)=4.076*fy*(EleCenter(I,2,1)-0.5)**2
EleIS(I,1,1)=EleIS(I,1,1)-0.719*fy
*IF,EleIS(I,1,1),LT,-0.3*fy,THEN
ELeIS(I,1,1)=-0.3*fy
*ENDIF


*ENDIF
*ENDIF
*ENDIF
*ENDIF
*ENDDO
===============
!输出应力数值
*CFOPEN,'1','txt',' '
*DO,I,1,3840
!*IF,EleIS(I,1,1),ne,0.,then
*VWRITE,'!'
(A)
*VWRITE,'! Stress for element',
(A,F)
*VWRITE,'!'
(A)
*VWRITE,'eis,',I
(A,F)
P=EleIS(I,1,1)
*VWRITE,P,0.,0.,0.,0.,0.
(E,E,E,E,E,E)
!*ENDIF
*ENDDO
*CFCLOS

说明:补充资料仅用于学习参考,请勿用于其它任何用途。
参考词条