1) variable eccentric compression judgment
大小偏心受压判别
2) little eccentric compression
小偏心受压
1.
Direct calculation of symmetric reinforcement for rectangular cross sectional little eccentric compression member;
矩形截面小偏心受压构件对称配筋的直接计算
3) limit of dimension eccentric compression
大小偏心受压的界限
1.
The limit of dimension eccentric compression under the situation of rectangle asymmetric reinforcement
矩形截面不对称配筋下大小偏心受压的界限
4) large eccentric compression
大偏心受压
1.
Calculation of bearing capacity for steel reinforced concrete=column subjected to large eccentric compression load;
钢骨混凝土大偏心受压柱承载力计算
5) distinguish in eccentricity
偏心判别
6) compression member with small eccentricity
小偏心受压构件
1.
The paper presents an approximate method of calculating ξ by using a first order multinomial of best approximation to simplify the basic formula in section design of symmetric reinforcement for compression member with small eccentricity,which results indicate that the method was higher accuracy and relative lower error than that of code s formula.
对小偏心受压构件在对称配筋情况下的截面配筋计算,提出用最佳一次逼近多项式简化基本公式,直接按二次方程求解ξ的近似方法,具有精度高,相对误差小,计算方便等优点,可供工程设计人员参考。
补充资料：在AutoCAD中偏心圆锥与偏心圆台实体的画法
现在要画一个偏心圆锥,底面在WCS的XY平面上,圆心(0,0,0),半径100,顶点(300,0,400)在ZX平面上.
1)连接PA,PB. A(-100,0,0) B(100,0,0)
图1
在当前坐标下:
2)延长PA到C,使PA=CA;延长PB到D,使PB=DB;
3)连接CD;
4)以CD为直径画圆;
5)用XLINE命令中的二等分选项作角CPD的角平分线PO,交CD于O;
6)过O作CD的垂线,交圆于E,F;
图2
7)用三点UCS命令,取三点为:O,P,C;
8)过点O作PO的垂线GO,交PC于G;
图3
9)再次用三点UCS命令,取三点为O,F,G;
10)现在就可以画椭圆锥了!
cone-e-c-捕捉O点-捕捉F点-捕捉G点-a-捕捉P点;
图4
11)回到WCS,剖切椭圆锥
SL-选择椭圆锥-回车-XY-回车-捕捉P点.
12)删除辅助线条.
图5
说明：补充资料仅用于学习参考，请勿用于其它任何用途。
参考词条