1) special matrix operation
![点击朗读](/dictall/images/read.gif)
矩阵特殊运算
1.
To determine the explicit form of integrands,the formulation of element matrices of high-order NMM is derived by using the special matrix operations including Kronecker product,Hadamard product and vectorization,resulting in a convenience of the.
采用Kronecker积、Hadamard积和拉直等矩阵特殊运算进行高阶流形单元分析,使得单元矩阵的推导过程简单且被积函数易表示为多项式形式。
2.
Based on the special matrix operations including Kronecker product, Hadamard product and vectorization, the integration of monomial integrand on simplex domain is expressed in matrix form and a recursive formula for the simplex integration is presented.
基于Kronecker积、Hadamard积和拉直等矩阵特殊运算,将单项式函数在单纯形上的积分表示为矩阵形式,提出了单纯形积分的递推公式。
2) particular matrix operation
![点击朗读](/dictall/images/read.gif)
特殊矩阵运算
3) special matrix
![点击朗读](/dictall/images/read.gif)
特殊矩阵
1.
In this paper, we give some notes of AA*=A*A= (detA)E which is a basic formula in studying matrix in proving solution of linearized equations, special matrix and so on through examples.
文章通过示例对矩阵公式AA*=A*A=(detA)E在求解线性方程组和特殊矩阵等方面的应用给出了几点注记。
2.
The special matrix refers to the matrix whose elements are special in the numerical value or in the property.
特殊矩阵是指矩阵元素在数值或其具有的性质上有特性的矩阵。
4) special matrices
![点击朗读](/dictall/images/read.gif)
特殊矩阵
1.
Finally, using another identity of 2Φ 0 , the numbers of some special matrices over F q are also obtained.
本文由有限域上交错矩阵方程XK2υX′=0的解数公式得到q超几何级数2Φ0的一个基本恒等式,并且用它能直接把一些特殊矩阵的这类方程的解数由函数2Φ0表出。
2.
The existence of solution for the linear complementarity problem is related with special matrices.
线性互补问题解的存在性,唯一性和各种实用算法都与特殊矩阵密切相关。
5) special symplectic matrix
![点击朗读](/dictall/images/read.gif)
特殊辛矩阵
6) matrix operation
![点击朗读](/dictall/images/read.gif)
矩阵运算
1.
A Method to Find the Transitive Closure of A Relation by Common Matrix Operation;
![点击朗读](/dictall/images/read.gif)
一种利用普通矩阵运算求传递闭包的方法
2.
The Realize of Matrix Operation Based on FPGA;
![点击朗读](/dictall/images/read.gif)
基于FPGA的矩阵运算实现
补充资料:不定积分的运算法则
又称为“不定积分的性质”,包含如下两个性质:
(1)设函数f(x)的原函数存在,k是常数,k≠0,则
∫kf(x)dx=k∫f(x)dx
(2)设f(x),g(x)是两个可积分的函数,则
∫[f(x)+g(x)]dx=∫f(x)dx+∫g(x)dx
说明:补充资料仅用于学习参考,请勿用于其它任何用途。
参考词条