1) consecutive positive integers
连续正整数
1.
The prime powers in sums of squares of 4k consecutive positive integers;
4k个连续正整数平方和中的素数方幂
2.
It was proved that there is unique solution on the prime or prime powers in sums of cubes of k consecutive positive integers.
证明了连续正整数的立方和为素数或素数方幂仅有惟一解。
3.
We prove that if 9 divides k or k is divisible by a prime q (q= ± 5 (mod 12)), then the sum of squares of any k consecutive positive integers cannot be a nth power of prime (n ∈ N).
对给定的正整数k,证明了:当9|k或q|k(q=±5(mod 12)是一个素数)时,任何k个连续正整数的平方和不是素数的n次幂(n∈N);当q|k(q=±1(mod 12)是一个素数)时,可定出模q的两个剩余类,而不属于其中任何一个剩余类的每一个非负整数x所确定的k个连续正整数的平方和(x+1)2+(x+2)2+…+(x+k)2不是素数的n次幂(n∈N)。
2) reciprocal of product of continuously positive integer
连续正整数之积的倒数
5) CCR
连续重整
1.
IMPACT OF PROCESSING HIGH RATIO HYDROTREATED COKER NAPHTHA IN CCR UNIT;
掺炼高比例加氢后焦化汽油对连续重整装置的影响
2.
APPLICATION OF ADVANCED PROCESS CONTROL IN CCR UNIT;
先进过程控制在连续重整装置中的应用
3.
Application of APC on CCR and Aromatic Extraction United Unit;
先进控制在某连续重整-芳烃抽提联合装置中的应用
6) Continuous Catalytic Reforming
连续重整
1.
The text analyses the energy consumption of Qilu 600 kt/a Continuous Catalytic Reforming Unit,finds out the reasons of higher energy consumption and presents modification measures,obtaining good results and providing a method and clue of thoughts for energy saving and consumption decreasing of the unit of the same kind.
对600 kt/a连续重整装置能耗进行分析,找出能耗偏高的原因。
2.
0 Mt/a continuous catalytic reforming unit of Huizhou refinery,and the content of chlorine in the regeneration gas is 0.
0 Mt/a连续重整装置的催化剂再生气排放量为1。
3.
It is concluded that the continuous catalytic reforming process is still the most competitive process in petroleum refining industry.
指出目前连续重整为最有竞争力的工艺,大力发展芳烃等石油化工行业,加快连续重整生产工艺的国产化,打破长期以来国外公司对连续重整技术的垄断,有利于我国催化重整的可持续发展。
补充资料：正整数
即“自然数”(1159页)。
说明：补充资料仅用于学习参考，请勿用于其它任何用途。
参考词条