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1)  weld [英][weld]  [美][wɛld]
2)  Deposit welding rod
堆焊焊条
1.
Research on the wear-resisting and heat-resisting deposit welding rode;
耐磨耐热堆条的制备研究
2.
The wear-resisting and heat-resisting deposit welding rod with Ni-Co-Cr-B-C as the basic alloy system was prepared by mechanical ball milling mixture, sintering after extrusion shaping method.
选择Ni-Co-Cr-B-C为基本合金体系,经过机械球磨混合、挤压成形、真空烧结方法制备了耐磨耐热堆条,采用钨极氩弧在高温铸造合金基材上堆耐磨耐热堆层,对堆层的组成、结构进行了分析,XRD分析和热力学计算表明层组成为Co、Ni为主的面心立方合金、M23(C,B)6或M23C6,还有少量的C7M3和M3B2。
3)  Hardfacing electrode
堆焊焊条
1.
Welding process of high temperature and non-slag hardfacing electrode;
高温无渣耐磨堆条的接工艺
2.
A hardfacing electrode containing boron and various alloy elements has been developed.
研制出一种含硼等多种合金元素的耐高温磨损堆条。
4)  surfacing electrode
堆焊焊条
1.
Development of wear resisting surfacing electrode with high efficiency,high hardness and low cost;
高效高硬度低成本耐磨堆条的研制
2.
Research on cavitation-resistant surfacing electrode;
Cr-Mn抗气蚀堆
3.
Research of alloy chute surfacing electrode;
合金溜槽堆条的研制
5)  wire/flux
焊剂/焊丝
6)  surfacing weld
堆焊焊缝
1.
The effects of alloy element C,Nb,Ti and V on the hardness and distribution of carbides in surfacing weld metal were investigated,and a kind of weld metal with high hardness was achieved.
研究了堆缝的硬度及碳化物分布,分析了C、Nb、Ti、V对硬度的影响,优选了一种硬度高、碳化物分布均匀的堆缝。
补充资料:ANSYS工字梁焊缝初应力例子

建立好模型
…..
/SOLU
!*
ANTYPE,0
/INPUT,'input','txt',
/INPUT,'output1','txt',
!*
ISFILE,READ,1,txt, ,0
SOLVE
=====================
!定义残余应力矩阵
I=1
fy=310e6
!定义单元中心坐标数组,初应力数组
*DIM,EleCenter,ARRAY,NumNode,3,1, , ,
*DIM,EleIS,ARRAY,NumNode,1,1, , ,
*DO,I, 1, NumNode,1
!得到单元中心坐标
*GET,EleCenter(I,1,1),ELEM,I,CENT,X
*GET,EleCenter(I,2,1),ELEM,I,CENT,Y
*GET,EleCenter(I,3,1),ELEM,I,CENT,Z
!焊缝位置在X=1.0 到1.05 之间
*IF,EleCenter(I,1,1),GT,1,THEN
*IF,EleCenter(I,1,1),LT,1.05,THEN
*IF,EleCenter(I,2,1),GT,0.5,THEN
!上翼缘初始应力
EleIS(I,1,1)=-20*fy*EleCenter(I,3,1)**2+0.3*fy
*endif
*IF,EleCenter(I,2,1),LT,0.0,THEN
!下翼缘初始应力
EleIS(I,1,1)=-20*fy*EleCenter(I,3,1)**2+0.3*fy
*endif
!腹板初始应力
*if,EleCenter(I,2,1),GE,0.0,THEN
*IF,ELECENTER(I,2,1),LE,0.5,THEN
EleIS(I,1,1)=4.076*fy*(EleCenter(I,2,1)-0.5)**2
EleIS(I,1,1)=EleIS(I,1,1)-0.719*fy
*IF,EleIS(I,1,1),LT,-0.3*fy,THEN
ELeIS(I,1,1)=-0.3*fy
*ENDIF


*ENDIF
*ENDIF
*ENDIF
*ENDIF
*ENDDO
===============
!输出应力数值
*CFOPEN,'1','txt',' '
*DO,I,1,3840
!*IF,EleIS(I,1,1),ne,0.,then
*VWRITE,'!'
(A)
*VWRITE,'! Stress for element',
(A,F)
*VWRITE,'!'
(A)
*VWRITE,'eis,',I
(A,F)
P=EleIS(I,1,1)
*VWRITE,P,0.,0.,0.,0.,0.
(E,E,E,E,E,E)
!*ENDIF
*ENDDO
*CFCLOS

说明:补充资料仅用于学习参考,请勿用于其它任何用途。
参考词条