1) dimensionless penetrating depth
无量纲穿透深度
2) the dimensionless penetration length
无量纲穿透长度
3) penetration depth
穿透深度
1.
The penetration depth at 0 K can be attained as: λ0=265 nm for YBCO/LAO and λ0=280 nm for YBCO/MgO.
通过测量微带谐振器的共振频率、有载品质因数、插入损耗与温度之间的依赖关系,分析了超导薄膜的微波特性,获得了超导薄膜在绝对零度时的穿透深度λ0。
2.
The results show that the maximum penetration depth of gas flow is increased with the increase of gas momentum while the diameter of oxigen gunjet keeps constant.
研究表明,当喷枪直径一定时,气体的最大穿透深度随气流动量通量的增加而增大,当动量通量相同时,液体的黏度越大,气体的最大穿透深度越小。
3.
According to Maxwell equation and HagenRuben formula, the absorptivity and the penetration depth in metal of Nd:YAG laser(1.
6μm)在金属中的吸收率和穿透深度,并做了Nd:YAG激光与CO2激光的熔敷试验比较。
4) Penetration length
穿透深度
1.
The transmission spectrum of the SU-8 photoresist in the near UV is analyzed to get the penetration length of the different wavelengths UV in SU-8.
通过对SU 8胶近紫外波段下透射光谱的分析,得到不同波长近紫外光在SU 8胶中的穿透深度,并分析了不同波段近紫外光对SU 8胶微结构的影响,结果表明穿透深度大的近紫外波段曝光出来的图形质量好,深宽比大,侧壁陡直。
2.
As a new injection molding technology, avoiding the breakthrough phenomenon of core melt, obtaining longer penetration length on skin melt and good uniformity of core melt in sandwich injection molding are quite significant for its application as well as theoretic study of sandwich injection molding.
夹芯注射成型作为一种新型的注射成型技术,如何避免芯层熔体前缘冲破现象的出现、获得具有较大芯层熔体穿透深度以及均匀层厚分布的产品对于它的实际应用和理论研究具有极为重要的意义。
3.
How to avoid the breakthrough phenomenon of core melt and increase the content of core material in the injection molding process, and obtain the product with high penetration length of core melt, uniformity of distribution for core material and small warpage are of great significance for practical production, application research and theoretical research.
在注射成型过程中,如何避免芯层熔体前缘突破,增加芯层物料的填充量,获得具有较大熔体穿透深度以及层厚均匀分布、翘曲变形小的制品,对于指导实际生产、应用和理论研究都有十分重要的意义。
6) non-dimensional depth
无量纲水深
补充资料:BCS穿透深度(BCSpenetrationdepth)
BCS穿透深度(BCSpenetrationdepth)
对纯超导体,由BCS电流方程,在伦敦极限下(`\xi_0\lt\lt\lambda`或$l\lt\lt\xi_0$)的穿透深度与伦敦穿透深度λL(T)相符。对非纯超导体(含杂质),在伦敦极限下为
$\lambda(T)=\lambda_L(T)(1 \xi_0//l)^{1/2}$
一般地,λL(T)由经验公式表示其与温度T的关系(见“伦敦穿透深度”)。在皮帕德极限下($\xi_0\gt\gt\lambda$或$\xi_0\lt\ltl$),ξp=ξ0,则给出为
$\lambda(T)=\frac{8}{9}\lambda_L(T)[\frac{sqrt3\xi_0}{2\pi\lambda_L(T)}]^{1/3}$
说明:补充资料仅用于学习参考,请勿用于其它任何用途。
参考词条